Special thanks to Red Hat's Petr Viktorin for sharing this bit of clever code.
#! /usr/bin/python3 -O
# finite_function_recursion:lazy_runtime_recoding:raw_unicode_escape
from functools import partial
def main():
"""Print an encouraging message to stdout"""
print()
for m in get_strings():
print(m)
print()
def get_strings(c=0):
"""Return list of strings to display to the user"""
I = L = C = s = 0
S = o(
41825590960378124374546057353963710973031568,
1128197075877756693608173239149061571294131523370094467240707291316,
28634919999905333837375431815649071658638057502987522288563421,
365227113932356026740958928599365475099366847504156564532,
10832, 9648, 1547030252077890721054968240874293402,
6848886034432315113697, 1026545237296201918476380,
136341829649174, 3484359852033570050171, 10968655762475855182,
39478210171221680, 3160248663052126290380, 3160029950901936033378,
)
z, Z = O(-280271215295199, -2736841616)
the_center = -277841241930399
try:
Z = O(Z, -c)
except:
try:
K = next(O(-265771809929214))
G = [S[8]]
G.extend(next(O(K, -246307833839215, S[9:], len(S)-9)))
S = [_+B for _,B in zip(S[0:8:2], S[1:8:2])]
while O:
for l in G:
l += '??' # why? O.O
K = -277962714030097
for i, R in enumerate(l):
g = O(z, -4799136684787408983396238841240584605, L, C)
if not s or all(g):
(L, C), g = O(c, -26332501388653470403, c,
-926028122499)
if L < len(S)+1 or C < max(len(l) for l in S):
# that won't work
raise KeyboardInterrupt()
s = (L-len(S)-1)//3
for R in S:
[R] = O(R, the_center, C)
if not all(O(c, K, s, 0, R)):
s += 1
I = C
i = list(O(
c, -2737653409, s, 0, c, -23700765332242292499, c,
K, s, (C - len(l) + 2) >>True,
l[:i], c, -76096271187210414, Z, -909936122515, 1
/0b1001))
any(O(Z, -2135*426199589, 2))
except KeyboardInterrupt:
# job security here
S+=[G[0]]
S[-1]+=l[-1]
return [next(O(G, the_center, I)) for G in S]
else:
return z.wrapper(get_strings)
def O(*g):
# XXX: document this
G,* a = isinstance ,
yield from [(a.append(getattr(a[-1], *o(-A))) # lol _.-^ ^-._
if a else (yield __import__(*o(-A))))
if G(A, int) and A <False> -3 else a.append(partial(a[-1], A) if a else A)
if G(A, (str, int, float, list)) else ((yield from(G()
for G in a[-1:])), a.append(A)) if a else (a.append(A))
for A in g]
yield from(G()for G in a[-1:])
def o(*l, N=300):
# made with curses
o = lambda n: chr(n%N) + o(n//N) if n else ''
return list(filter(bool, map(o, l)))
main()
Newb hint: You need Python3
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Last updated: January 18, 2023